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1400=700x-x^2
We move all terms to the left:
1400-(700x-x^2)=0
We get rid of parentheses
x^2-700x+1400=0
a = 1; b = -700; c = +1400;
Δ = b2-4ac
Δ = -7002-4·1·1400
Δ = 484400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{484400}=\sqrt{400*1211}=\sqrt{400}*\sqrt{1211}=20\sqrt{1211}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-700)-20\sqrt{1211}}{2*1}=\frac{700-20\sqrt{1211}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-700)+20\sqrt{1211}}{2*1}=\frac{700+20\sqrt{1211}}{2} $
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